Morphocompletion for #6177 ⟨a, b, c | aa=1, abcacb=1⟩

Solved by morph:2/0. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: roundsLimit

#Rule
1. aa ⇒ 1
2. babc ⇒ acbaba
3. cacbab ⇒ 1
4. bcac ⇒ acacba
5. cacbcbab ⇒ abca
6. cacbcbcbab ⇒ abcbca
7. cacbcbcbcbab ⇒ abcbcbca
8. cacbcbcbcbaba ⇒ abcbcbc
9. cacbcbcbcbcbab ⇒ abcbcbcbca
10. cacbcbcbcbcbaba ⇒ abcbcbcbc
11. cacbcbcbcbcbcbab ⇒ abcbcbcbcbca
12. cacbcbcbcbcbcbaba ⇒ abcbcbcbcbc
13. cacbcbcbcbcbcbcbab ⇒ abcbcbcbcbcbca
14. cacbcbcbcbcbcbcbaba ⇒ abcbcbcbcbcbc
...

Collecting factors up to length 4 / frequency 7:

[2/0]cb50lf:50,rf:31,a:5
[2/1]bc43lf:41,lp:1,ls:1,rf:39,rs:4,a:5
[2/2]ca23lf:12,lp:11,rf:7,rs:6,lprs:6,a:5
[2/3]ba21lf:16,lp:1,ls:4,rf:3,rs:2,lprs:1,a:5
[2/4]ab19lf:12,ls:7,rf:11,rp:10,lsrp:6,a:9
[2/5]ac13lf:12,ls:1,rf:3,rp:2,lsrp:1,a:5
[3/0]cbc39lf:39,rf:29,rs:4,a:11
[3/1]bcb39lf:39,rf:29,a:11
[3/2]cac24lf:12,lp:11,ls:1,rf:1,a:5
[3/3]bab20lf:12,lp:1,ls:7,rf:1,a:9
[3/4]acb11lf:11,rf:2,rp:1,a:5
[3/5]cba11lf:11,rf:2,rs:1,a:5
[3/6]aba8lf:4,ls:4,rf:1,rs:1,a:16

Considering [length 2 / frequency 0] cb=d.

Step 2

Rewriting system is complete. See ⟨a, b, c | aa=1, abcacb=1⟩.