| Back: | ⟨a, b, c | aa=1, abcacb=1⟩ |
|---|
Completion settings:
Axiom: aa=1.
Defines rule #1.
Referenced by [5], [9], [11], [13], [16], [17], [19].
Axiom: abcacb=1.
Referenced by [4].
Axiom: cb=d.
Defines rule #3.
Referenced by [4], [6], [10], [18], [20].
Overlap of [2] abcacb=1 with [3] cb=d:
Critical pair: abcad=1.
Referenced by [5].
Overlap of [1] aa=1 with [4] abcad=1:
Critical pair: a=bcad.
Flip LHS and RHS.
Defines rule #8.
Referenced by [6], [7], [10], [14], [16].
Overlap of [3] cb=d with [5] bcad=a:
Critical pair: ca=dcad.
Flip LHS and RHS.
Defines rule #10.
Overlap of [5] bcad=a with [6] dcad=ca:
Critical pair: bcaca=acad.
Overlap of [6] dcad=ca with [6] dcad=ca:
Critical pair: dcaca=cacad.
Flip LHS and RHS.
Defines rule #12.
Referenced by [16].
Overlap of [7] bcaca=acad with [1] aa=1:
Critical pair: bcac=acada.
Defines rule #9.
Referenced by [10].
Overlap of [9] bcac=acada with [3] cb=d:
Critical pair: bcad=acadab.
Reduce LHS:
| [5] | (bcad) |
| ⇒ a |
Flip LHS and RHS.
Overlap of [1] aa=1 with [10] acadab=a:
Critical pair: aa=cadab.
Reduce LHS:
| [1] | (aa) |
| ⇒ 1 |
Flip LHS and RHS.
Defines rule #7.
Referenced by [15].
Overlap of [7] bcaca=acad with [10] acadab=a:
Critical pair: bca=acaddab.
Flip LHS and RHS.
Referenced by [13].
Overlap of [1] aa=1 with [12] acaddab=bca:
Critical pair: abca=caddab.
Flip LHS and RHS.
Referenced by [14], [15], [16].
Overlap of [5] bcad=a with [13] caddab=abca:
Critical pair: babca=adab.
Referenced by [19].
Overlap of [6] dcad=ca with [13] caddab=abca:
Critical pair: dabca=cadab.
Reduce RHS:
| [11] | (cadab) |
| ⇒ 1 |
Referenced by [17].
Overlap of [13] caddab=abca with [5] bcad=a:
Critical pair: caddaa=abcacad.
Reduce LHS:
| [1] | cadd(aa) |
| ⇒ cadd |
Reduce RHS:
| [8] | ab(cacad) |
| ⇒ abdcaca |
Defines rule #11.
Overlap of [15] dabca=1 with [1] aa=1:
Critical pair: dabc=a.
Defines rule #6.
Referenced by [18].
Overlap of [17] dabc=a with [3] cb=d:
Critical pair: dabd=ab.
Defines rule #5.
Overlap of [14] babca=adab with [1] aa=1:
Critical pair: babc=adaba.
Defines rule #4.
Referenced by [20].
Overlap of [19] babc=adaba with [3] cb=d:
Critical pair: babd=adabab.
Defines rule #2.