Morphocompletion for #4873 ⟨a, b, c | ab=a, bbccb=1⟩

Solved by morph:3/0. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: roundsLimit

#Rule
1. ab ⇒ a
2. cbbb ⇒ bbbc
3. acbbb ⇒ ac
4. acc ⇒ a
5. bbbcc ⇒ 1
6. ccb ⇒ bcc
7. acbcc ⇒ acb
8. bbbcbcc ⇒ cb
9. acbbcc ⇒ acbb
10. bbbcbbcc ⇒ cbb
11. acbcbcc ⇒ acbcb
12. bbbcbcbcc ⇒ cbcb
13. acbbcbcc ⇒ acbbcb
14. bbbcbbcbcc ⇒ cbbcb
15. acbcbbcc ⇒ acbcbb
16. bbbcbcbbcc ⇒ cbcbb
17. acbbcbbcc ⇒ acbbcbb
...

Collecting factors up to length 4 / frequency 7:

[2/0]bb32lf:24,lp:6,ls:2,rf:10,rp:1,rs:5,lsrp:1,lprs:2,a:7
[2/1]cc28lf:14,lp:1,ls:13,rf:1,rs:1,lprs:10,a:4
[2/2]bc24lf:24,rf:9,rp:1,rs:1,a:5
[2/3]cb23lf:21,lp:1,ls:1,rf:18,rp:5,rs:6,re:1,a:5
[2/4]ac16lf:8,lp:8,rf:7,rp:7,rs:1,re:1,lprp:7,lprs:1,a:4
[3/0]bcc24lf:12,ls:12,rf:1,rp:1,rs:1,re:1,a:5
[3/1]bbb16lf:8,lp:6,ls:2,rf:1,rp:1,lsrp:10,a:9
[3/2]acb14lf:7,lp:7,rf:6,rp:6,rs:1,re:1,lprp:6,lprs:1,a:6
[3/3]bbc14lf:14,rf:4,rs:1,a:7
[3/4]bcb12lf:12,rf:7,rs:4,a:8
[3/5]cbb11lf:10,lp:1,rf:8,rp:2,rs:5,re:1,a:7
[3/6]cbc10lf:10,rf:4,rp:2,a:6

Considering [length 3 / frequency 0] bcc=d.

Step 2

Rewriting system is complete. See ⟨a, b, c | ab=a, bbccb=1⟩.