Morphocompletion for #2726 ⟨a, b, c | abc=a, bccb=1⟩

Solved by morph:2/0. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: roundsLimit

#Rule
1. acb ⇒ a
2. abc ⇒ a
3. bbc ⇒ cbb
4. ccbb ⇒ 1
5. accb ⇒ ac
6. bcc ⇒ ccb
7. ccbcbb ⇒ bc
8. acccb ⇒ acc
9. ccbcbcbb ⇒ bcbc
10. accccb ⇒ accc
11. ccbcbcbcbb ⇒ bcbcbc
12. acccccb ⇒ acccc
13. ccbcbcbcbcbb ⇒ bcbcbcbc
14. accccccb ⇒ accccc
15. ccbcbcbcbcbcbb ⇒ bcbcbcbcbc
16. acccccccb ⇒ acccccc
17. accccccccb ⇒ accccccc
18. acccccccccb ⇒ acccccccc
19. accccccccccb ⇒ accccccccc
...

Collecting factors up to length 4 / frequency 7:

[2/0]cc59lf:52,lp:6,ls:1,rf:37,rp:1,rs:8,lsrp:10,a:3
[2/1]cb41lf:31,ls:10,rf:12,rp:1,rs:1,a:2
[2/2]bc21lf:18,lp:1,ls:2,rf:15,rp:5,rs:5,re:1
[2/3]ac20lf:10,lp:10,rf:9,rp:9,rs:1,re:1,lprp:9,lprs:1,a:2
[2/4]bb14lf:7,lp:1,ls:6,rf:1,rs:1,lprs:10,a:6
[2/5]ab2lf:1,lp:1
[3/0]ccc36lf:36,rf:28,rs:7,a:5
[3/1]ccb30lf:15,lp:6,ls:9,rf:1,rp:1,rs:1,re:1,a:3
[3/2]acc18lf:9,lp:9,rf:8,rp:8,rs:1,re:1,lprp:8,lprs:1,a:4
[3/3]cbc15lf:15,rf:10,rs:4,a:8
[3/4]bcb15lf:15,rf:10,rp:4,a:8
[3/5]cbb12lf:6,ls:6,rf:1,rp:1,rs:1,re:1,a:6

Considering [length 2 / frequency 0] cc=d.

Step 2

Rewriting system is complete. See ⟨a, b, c | abc=a, bccb=1⟩.