Certificate for #2621 ⟨a, b, c | aba=b, bccb=1⟩

Completion settings:

[1] aba=b

Axiom: aba=b.

Defines rule #5.

Referenced by [5].

[2] bccb=1

Axiom: bccb=1.

Referenced by [6], [7], [8], [9], [11].

[3] bb=d

Axiom: bb=d.

Defines rule #1.

Referenced by [4], [5], [7], [8].

[4] db=bd

Overlap of [3] bb=d with [3] bb=d:

b b bb

Critical pair: bd=db.

Flip LHS and RHS.

Defines rule #3.

Referenced by [8].

[5] da=ad

Overlap of [1] aba=b with [1] aba=b:

ab a aba

Critical pair: abb=bba.

Reduce LHS:

[3]a(bb)
⇒ ad

Reduce RHS:

[3](bb)a
⇒ da

Flip LHS and RHS.

Defines rule #2.

Referenced by [10].

[6] ccb=bcc

Overlap of [2] bccb=1 with [2] bccb=1:

bcc b bccb

Critical pair: bcc=ccb.

Flip LHS and RHS.

Defines rule #7.

Referenced by [8].

[7] bccd=b

Overlap of [2] bccb=1 with [3] bb=d:

bcc b bb

Critical pair: bccd=b.

Referenced by [9].

[8] bdcc=b

Overlap of [3] bb=d with [2] bccb=1:

b b bccb

Critical pair: b=dccb.

Reduce RHS:

[6]d(ccb)
[4]⇒ (db)cc
⇒ bdcc

Flip LHS and RHS.

Referenced by [11].

[9] ccd=1

Overlap of [2] bccb=1 with [7] bccd=b:

bcc b bccd

Critical pair: bccb=ccd.

Reduce LHS:

[2](bccb)
⇒ 1

Flip LHS and RHS.

Defines rule #8.

Referenced by [10], [12], [14].

[10] ccad=a

Overlap of [9] ccd=1 with [5] da=ad:

cc d da

Critical pair: ccad=a.

Referenced by [13].

[11] dcc=1

Overlap of [2] bccb=1 with [8] bdcc=b:

bcc b bdcc

Critical pair: bccb=dcc.

Reduce LHS:

[2](bccb)
⇒ 1

Flip LHS and RHS.

Referenced by [12].

[12] dc=cd

Overlap of [11] dcc=1 with [9] ccd=1:

dc c ccd

Critical pair: dc=cd.

Defines rule #4.

Referenced by [13], [14].

[13] ccacd=ac

Overlap of [10] ccad=a with [12] dc=cd:

cca d dc

Critical pair: ccacd=ac.

Referenced by [14].

[14] cca=acc

Overlap of [13] ccacd=ac with [12] dc=cd:

ccac d dc

Critical pair: ccaccd=acc.

Reduce LHS:

[9]cca(ccd)
⇒ cca

Defines rule #6.