Morphocompletion for #1997 ⟨a, b, c | abc=bb, cba=1⟩

Solved by morph:2/1. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: roundsLimit

#Rule
1. bbba ⇒ ab
2. bc ⇒ cbbb
3. acbb ⇒ b
4. acbbb ⇒ bb
5. bac ⇒ acb
6. bacbb ⇒ bb
7. bbac ⇒ acbb
8. cba ⇒ 1
9. baacbb ⇒ bab
10. acab ⇒ bba
11. acbbab ⇒ bab
12. cacb ⇒ c
13. caccbbb ⇒ cc
...

Collecting factors up to length 4 / frequency 7:

[2/0]bb18lf:11,lp:2,ls:5,rf:6,rp:3,rs:4,re:2,lsrp:2,lprs:1,lsrs:2,a:2
[2/1]ac16lf:10,lp:4,ls:2,rf:2,rp:2,lsrp:11,a:4
[2/2]ba12lf:7,lp:3,ls:2,rf:3,rp:2,rs:1,lprp:1,a:1
[2/3]cb10lf:8,lp:1,ls:1,rf:3,rp:1,rs:1,a:1
[2/4]ca5lf:3,lp:2,a:5
[2/5]ab4lf:2,ls:2,rf:3,rp:1,rs:3,re:1,lsrs:1,a:2
[2/6]cc1lf:1,rf:1,rp:1,rs:1,re:1,a:24
[3/0]acb10lf:6,lp:3,ls:1,rf:2,rp:2,rs:1,re:1,a:4
[3/1]cbb9lf:6,ls:3,rf:2,rp:1,rs:1,a:3
[3/2]bbb6lf:3,lp:1,ls:2,rf:1,rs:1,a:2
[3/3]bba5lf:3,lp:1,ls:1,rf:1,rp:1,rs:1,re:1,a:2
[3/4]cac4lf:2,lp:2,a:22
[3/5]bac4lf:2,lp:1,ls:1,a:9
[3/6]aca2lf:1,lp:1,a:5

Considering [length 2 / frequency 1] ac=d.

Step 2

Rewriting system is complete. See ⟨a, b, c | abc=bb, cba=1⟩.