Certificate for #1602 ⟨a, b | aaa=bb, aba=a⟩

Completion settings:

[1] aaa=bb

Axiom: aaa=bb.

Defines rule #5.

Referenced by [3], [4], [5], [6].

[2] aba=a

Axiom: aba=a.

Defines rule #4.

Referenced by [4], [5].

[3] bba=abb

Overlap of [1] aaa=bb with [1] aaa=bb:

a aa aaa

Critical pair: abb=bba.

Flip LHS and RHS.

Referenced by [4], [7], [8], [9].

[4] babb=bb

Overlap of [1] aaa=bb with [2] aba=a:

aa a aba

Critical pair: aaa=bbba.

Reduce LHS:

[1](aaa)
⇒ bb

Reduce RHS:

[3]b(bba)
⇒ babb

Flip LHS and RHS.

Referenced by [7], [8].

[5] abbb=bb

Overlap of [2] aba=a with [1] aaa=bb:

ab a aaa

Critical pair: abbb=aaa.

Reduce RHS:

[1](aaa)
⇒ bb

Referenced by [6], [8].

[6] aabb=bbbbb

Overlap of [1] aaa=bb with [5] abbb=bb:

aa a abbb

Critical pair: aabb=bbbbb.

Referenced by [7], [8].

[7] abb=bbbbbb

Overlap of [4] babb=bb with [3] bba=abb:

ba bb bba

Critical pair: baabb=bba.

Reduce LHS:

[6]b(aabb)
⇒ bbbbbb

Reduce RHS:

[3](bba)
⇒ abb

Flip LHS and RHS.

Defines rule #2.

Referenced by [9].

[8] bbbbbbb=bb

Overlap of [5] abbb=bb with [3] bba=abb:

abb b bba

Critical pair: abbabb=bbba.

Reduce LHS:

[3]a(bba)bb
[6]⇒ (aabb)bb
⇒ bbbbbbb

Reduce RHS:

[3]b(bba)
[4]⇒ (babb)
⇒ bb

Defines rule #1.

[9] bba=bbbbbb

Simplify [3] bba=abb.

Reduce RHS:

[7](abb)
⇒ bbbbbb

Defines rule #3.