#1925 ⟨a, b | aaabbbaa=ba⟩

Quick links

Presentation has sum-of-sides 10
Infinite non-cancellative non-commutative monoid
Not right cancellative, because right multiplication by a is not injective:
- a³b³a ⋅ a = ba and b ⋅ a = ba, however a³b³a ≠ b
Enveloping group: ⟨a, b | aaabab^-1b^-1b^-1⟩

Format:	Pretty Plain
Word to reduce:
	Tips: Lowercase letters stand for generators. Spaces are ignored. Numbers repeat the previous letter, e.g. `b90`.
Reduction strategy:	Leftmost Rightmost
Path to normal form:	1 1

Auxiliary generators:
1. c = bbba
Reduction order:
- Right-to-left recursive path with deg(a) = deg(c) = 0, a < c; deg(b) = 1
Certificate: derivations of all rewriting rules from the defining relations.
Morphocompletion: how the auxiliary generators were found.

# ab:aaabbbaa=ba reversed:ac/b bbba=c morph:4/0
aaacc=caaca
aaacaaacaaaca=c
ba=aaaca
bc=caaca

Up:	Monoids with two generators and one relation
Prev:	#1924 ⟨a, b \| aaabbbaa=ab⟩
Next:	#1926 ⟨a, b \| aaabbbaa=bb⟩