Morphocompletion for #1925 ⟨a, b | aaabbbaa=ba

Solved by morph:4/0. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: rulesLimit

#Rule
1. aaabbbaa ⇒ ba
2. aaabbbaba ⇒ bba
3. baabbbaa ⇒ aaabbbba
4. aaabbbabba ⇒ bbba
5. baabbbaba ⇒ aaabbbbba
6. aaabbaaabbbba ⇒ babbbaa
7. aaabbbabbba ⇒ bbbba
8. baabbbabba ⇒ aaabbbbbba
9. aaabbaaabbbbba ⇒ babbbaba
10. aaabbbabbbba ⇒ bbbbba
11. baabbbabbba ⇒ aaabbbbbbba
12. aaabbbbabbbaa ⇒ baabbaaabbbba
13. aaabbaaabbbbbba ⇒ babbbabba
14. aaabbbabbbbba ⇒ bbbbbba
15. baabbbabbbba ⇒ aaabbbbbbbba
16. aaabbbabbbbbba ⇒ bbbbbbba
17. aaabbbabbbbbbba ⇒ bbbbbbbba
...

Collecting factors up to length 8, frequency 7:

Length 2:[2/0] bb, [2/1] ba, [2/2] aa, [2/3] ab
Length 3:[3/0] bbb, [3/1] bba, [3/2] abb, [3/3] aaa, [3/4] aab, [3/5] baa, [3/6] bab
Length 4:[4/0] bbba, [4/1] aaab, [4/2] abbb, [4/3] aabb, [4/4] bbbb, [4/5] bbab, [4/6] babb
Length 5:[5/0] aaabb, [5/1] abbba, [5/2] bbbba, [5/3] aabbb, [5/4] bbbab, [5/5] bbabb, [5/6] baabb
Length 6:[6/0] aaabbb, [6/1] aabbba, [6/2] abbbab, [6/3] bbbbba, [6/4] bbbabb, [6/5] baabbb, [6/6] bbabbb
Length 7:[7/0] aaabbba, [7/1] aabbbab, [7/2] baabbba, [7/3] abbbabb, [7/4] bbbabbb, [7/5] bbbbbba, [7/6] aaabbaa

Considering [length 4 / frequency 0] bbba=c.

Step 2

Rewriting system is complete. See a, b | aaabbbaa=ba.