| Back: | ⟨a, b | aaabbbaa=ba⟩ |
|---|
Solved by morph:4/0. (See Morphocompletion.)
Checking up to 20 rules for overlaps.
Rewriting system is not complete: rulesLimit
| # | Rule |
|---|---|
| 1. | aaabbbaa ⇒ ba |
| 2. | aaabbbaba ⇒ bba |
| 3. | baabbbaa ⇒ aaabbbba |
| 4. | aaabbbabba ⇒ bbba |
| 5. | baabbbaba ⇒ aaabbbbba |
| 6. | aaabbaaabbbba ⇒ babbbaa |
| 7. | aaabbbabbba ⇒ bbbba |
| 8. | baabbbabba ⇒ aaabbbbbba |
| 9. | aaabbaaabbbbba ⇒ babbbaba |
| 10. | aaabbbabbbba ⇒ bbbbba |
| 11. | baabbbabbba ⇒ aaabbbbbbba |
| 12. | aaabbbbabbbaa ⇒ baabbaaabbbba |
| 13. | aaabbaaabbbbbba ⇒ babbbabba |
| 14. | aaabbbabbbbba ⇒ bbbbbba |
| 15. | baabbbabbbba ⇒ aaabbbbbbbba |
| 16. | aaabbbabbbbbba ⇒ bbbbbbba |
| 17. | aaabbbabbbbbbba ⇒ bbbbbbbba |
| ... |
Collecting factors up to length 8, frequency 7:
| Length 2: | [2/0] bb, [2/1] ba, [2/2] aa, [2/3] ab |
|---|---|
| Length 3: | [3/0] bbb, [3/1] bba, [3/2] abb, [3/3] aaa, [3/4] aab, [3/5] baa, [3/6] bab |
| Length 4: | [4/0] bbba, [4/1] aaab, [4/2] abbb, [4/3] aabb, [4/4] bbbb, [4/5] bbab, [4/6] babb |
| Length 5: | [5/0] aaabb, [5/1] abbba, [5/2] bbbba, [5/3] aabbb, [5/4] bbbab, [5/5] bbabb, [5/6] baabb |
| Length 6: | [6/0] aaabbb, [6/1] aabbba, [6/2] abbbab, [6/3] bbbbba, [6/4] bbbabb, [6/5] baabbb, [6/6] bbabbb |
| Length 7: | [7/0] aaabbba, [7/1] aabbbab, [7/2] baabbba, [7/3] abbbabb, [7/4] bbbabbb, [7/5] bbbbbba, [7/6] aaabbaa |
Considering [length 4 / frequency 0] bbba=c.
Rewriting system is complete. See ⟨a, b | aaabbbaa=ba⟩.