Morphocompletion for #1925 ⟨a, b | aaabbbaa=ba⟩

Solved by morph:4/0. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: rulesLimit

#Rule
1. aaabbbaa ⇒ ba
2. aaabbbaba ⇒ bba
3. baabbbaa ⇒ aaabbbba
4. aaabbbabba ⇒ bbba
5. baabbbaba ⇒ aaabbbbba
6. aaabbaaabbbba ⇒ babbbaa
7. aaabbbabbba ⇒ bbbba
8. baabbbabba ⇒ aaabbbbbba
9. aaabbaaabbbbba ⇒ babbbaba
10. aaabbbabbbba ⇒ bbbbba
11. baabbbabbba ⇒ aaabbbbbbba
12. aaabbbbabbbaa ⇒ baabbaaabbbba
13. aaabbaaabbbbbba ⇒ babbbabba
14. aaabbbabbbbba ⇒ bbbbbba
15. baabbbabbbba ⇒ aaabbbbbbbba
16. aaabbbabbbbbba ⇒ bbbbbbba
17. aaabbbabbbbbbba ⇒ bbbbbbbba
...

Collecting factors up to length 8 / frequency 7:

[2/0]bb73lf:73,rf:64,rp:7
[2/1]ba56lf:37,lp:5,ls:14,rf:24,rp:5,rs:16,re:1,lsrp:3,lprs:5,lsrs:13
[2/2]aa53lf:38,lp:12,ls:3,rf:14,rp:5,rs:1,lsrp:1,lprs:1
[2/3]ab32lf:32,rf:12
[3/0]bbb43lf:43,rf:46,rp:6
[3/1]bba42lf:30,ls:12,rf:18,rp:1,rs:14,re:1,lsrs:10
[3/2]abb30lf:30,rf:11
[3/3]aaa27lf:15,lp:12,rf:6,rp:5
[3/4]aab20lf:20,rf:7
[3/5]baa19lf:11,lp:5,ls:3,rf:3,rp:1,rs:1,lsrp:1
[3/6]bab12lf:12,rf:5,rp:3,a:2
[4/0]bbba35lf:25,ls:10,rf:15,rp:1,rs:12,re:1,lsrs:7
[4/1]aaab27lf:15,lp:12,rf:6,rp:5
[4/2]abbb25lf:25,rf:9
[4/3]aabb20lf:20,rf:7
[4/4]bbbb18lf:18,rf:31,rp:5,a:1
[4/5]bbab12lf:12,rf:2,a:2
[4/6]babb10lf:10,rf:4,rp:3,a:4
[5/0]aaabb27lf:15,lp:12,rf:6,rp:5
[5/1]abbba18lf:16,ls:2,rf:3
[5/2]bbbba17lf:9,ls:8,rf:11,rp:1,rs:11,re:1,lsrs:5,a:1
[5/3]aabbb17lf:17,rf:6
[5/4]bbbab12lf:12,rf:2,a:2
[5/5]bbabb10lf:10,rf:1,a:4
[5/6]baabb10lf:5,lp:5,rf:1,rp:1,a:1
[6/0]aaabbb21lf:12,lp:9,rf:6,rp:5
[6/1]aabbba13lf:13
[6/2]abbbab11lf:11,rf:2,a:2
[6/3]bbbbba10lf:5,ls:5,rf:8,rp:1,rs:8,re:1,lsrs:3,a:3
[6/4]bbbabb10lf:10,rf:1,a:4
[6/5]baabbb10lf:5,lp:5,a:1
[6/6]bbabbb8lf:8,a:5
[7/0]aaabbba16lf:8,lp:8
[7/1]aabbbab11lf:11,a:2
[7/2]baabbba10lf:5,lp:5,a:1
[7/3]abbbabb9lf:9,rf:1,a:4
[7/4]bbbabbb8lf:8,a:5
[7/5]bbbbbba6lf:3,ls:3,rf:6,rp:1,rs:6,re:1,lsrs:2,a:6
[7/6]aaabbaa6lf:3,lp:3,a:9

Considering [length 4 / frequency 0] bbba=c.

Step 2

Rewriting system is complete. See ⟨a, b | aaabbbaa=ba⟩.