| Up: | Monoid enumeration |
|---|---|
| Next: | #2 ⟨a, b | baababa=a⟩ |
| # | Rule | Proof |
|---|---|---|
| 1. | ca ⇒ ac | [12] |
| 2. | b2a ⇒ c | [2] |
| 3. | cbac ⇒ abc2 | [8] |
| 4. | cbabc2 ⇒ ba | [4] |
| 5. | ba2 ⇒ (ab)2c3 | [13] |
| 6. | (ba)2c ⇒ aba(bc2)2 | [10] |
| 7. | b(ab)2c2 ⇒ a | [3] |
| 8. | c(ba)2 ⇒ abcba | [9] |
| 9. | cbabcba ⇒ a | [6] |
| 10. | (ba)3 ⇒ (ab)2c(cb)2a | [11] |
| 11. | b(ab)2cba ⇒ (ab)2c2 | [5] |
# ab:bababbbabba=a bc/a bba=c custom:0 ca=ac bba=c cbac=abcc cbabcc=ba baa=ababccc babac=ababccbcc bababcc=a cbaba=abcba cbabcba=a bababa=ababccbcba bababcba=ababcc
Axiom: bababbbabba=a.
Referenced by [3].
Axiom: bba=c.
Defines rule #2.
Referenced by [3], [4], [8], [12].
Overlap of [1] bababbbabba=a with [2] bba=c:
Critical pair: bababcbba=a.
Reduce LHS:
| [2] | bababc(bba) |
| ⇒ bababcc |
Defines rule #7.
Referenced by [4], [5], [6], [12].
Overlap of [2] bba=c with [3] bababcc=a:
Critical pair: cbabcc=ba.
Defines rule #4.
Referenced by [5], [6], [7], [8], [10], [11], [12], [13].
Overlap of [3] bababcc=a with [4] cbabcc=ba:
Critical pair: ababcc=bababcba.
Flip LHS and RHS.
Defines rule #11.
Referenced by [7].
Overlap of [4] cbabcc=ba with [4] cbabcc=ba:
Critical pair: bababcc=cbabcba.
Reduce LHS:
| [3] | (bababcc) |
| ⇒ a |
Flip LHS and RHS.
Defines rule #9.
Overlap of [4] cbabcc=ba with [6] cbabcba=a:
Critical pair: bababcba=cbabca.
Reduce LHS:
| [5] | (bababcba) |
| ⇒ ababcc |
Flip LHS and RHS.
Referenced by [10], [11], [13].
Overlap of [6] cbabcba=a with [4] cbabcc=ba:
Critical pair: abcc=cbabba.
Reduce RHS:
| [2] | cba(bba) |
| ⇒ cbac |
Flip LHS and RHS.
Defines rule #3.
Referenced by [10].
Overlap of [6] cbabcba=a with [6] cbabcba=a:
Critical pair: abcba=cbaba.
Flip LHS and RHS.
Defines rule #8.
Overlap of [4] cbabcc=ba with [8] cbac=abcc:
Critical pair: babac=cbabcabcc.
Reduce RHS:
| [7] | (cbabca)bcc |
| ⇒ ababccbcc |
Defines rule #6.
Overlap of [4] cbabcc=ba with [9] cbaba=abcba:
Critical pair: bababa=cbabcabcba.
Reduce RHS:
| [7] | (cbabca)bcba |
| ⇒ ababccbcba |
Defines rule #10.
Overlap of [9] cbaba=abcba with [3] bababcc=a:
Critical pair: abcbabcc=ca.
Reduce LHS:
| [4] | ab(cbabcc) |
| [2] | ⇒ a(bba) |
| ⇒ ac |
Flip LHS and RHS.
Defines rule #1.
Referenced by [13].
Overlap of [4] cbabcc=ba with [12] ca=ac:
Critical pair: baa=cbabcac.
Reduce RHS:
| [7] | (cbabca)c |
| ⇒ ababccc |
Defines rule #5.