Morphocompletion for #7847 ⟨a, b, c | ab=1, cba=bac⟩

Solved by morph:2/1. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: roundsLimit

#Rule
1. ab ⇒ 1
2. acba ⇒ ac
3. bac ⇒ cba
4. accba ⇒ acc
5. acccba ⇒ accc
6. accccba ⇒ acccc
7. acccccba ⇒ accccc
8. accccccba ⇒ acccccc
9. acccccccba ⇒ accccccc
10. accccccccba ⇒ acccccccc
11. acccccccccba ⇒ accccccccc
12. accccccccccba ⇒ acccccccccc
13. acccccccccccba ⇒ accccccccccc
14. accccccccccccba ⇒ acccccccccccc
15. acccccccccccccba ⇒ accccccccccccc
16. accccccccccccccba ⇒ acccccccccccccc
17. acccccccccccccccba ⇒ accccccccccccccc
18. accccccccccccccccba ⇒ acccccccccccccccc
19. acccccccccccccccccba ⇒ accccccccccccccccc
20. accccccccccccccccccba ⇒ acccccccccccccccccc
...

Collecting factors up to length 4 / frequency 7:

[2/0]cc153lf:153,rf:153,rs:17,a:3
[2/1]ac38lf:19,lp:18,ls:1,rf:18,rp:18,rs:1,re:1,lprp:18,lprs:1,a:1
[2/2]ba38lf:19,lp:1,ls:18,rf:1,rs:1,lprs:10,a:1
[2/3]cb18lf:18,rf:1,rp:1,a:1
[3/0]ccc136lf:136,rf:136,rs:16,a:4
[3/1]cba36lf:18,ls:18,rf:1,rp:1,rs:1,re:1,a:1
[3/2]acc34lf:17,lp:17,rf:17,rp:17,rs:1,re:1,lprp:17,lprs:1,a:3
[3/3]ccb17lf:17,a:3
[3/4]acb2lf:1,lp:1,a:2

Considering [length 2 / frequency 1] ac=d.

Step 2

Rewriting system is complete. See ⟨a, b, c | ab=1, cba=bac⟩.