Morphocompletion for #7837 ⟨a, b, c | ab=1, cac=bba⟩

Solved by morph:2/0. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: roundsLimit

#Rule
1. ab ⇒ 1
2. bacb ⇒ cb
3. baccb ⇒ ccb
4. bacccb ⇒ cccb
5. baccccb ⇒ ccccb
6. bacccccb ⇒ cccccb
7. cacb ⇒ bb
8. caccb ⇒ bcb
9. cacccb ⇒ bccb
10. caccccb ⇒ bcccb
11. cacccccb ⇒ bccccb
12. bba ⇒ cac
13. acac ⇒ ba
14. baac ⇒ acba
15. baccac ⇒ ccac
16. bacccac ⇒ cccac
17. caccac ⇒ bcac
18. cacccac ⇒ bccac
19. aacba ⇒ aac
...

Collecting factors up to length 4 / frequency 7:

[2/0]ac29lf:22,lp:1,ls:6,rf:7,rp:1,rs:6,lsrp:1,lsrs:4,a:1
[2/1]cc26lf:26,rf:20,rp:6,a:4
[2/2]cb21lf:11,ls:10,rf:10,rp:1,rs:9,re:1,lsrp:1,lsrs:9,a:3
[2/3]ba20lf:10,lp:8,ls:2,rf:2,rp:1,rs:2,re:1,lprs:1,a:1
[2/4]ca19lf:12,lp:7,rf:5,rp:1,a:1
[2/5]aa3lf:2,lp:1,rf:1,rp:1,lprp:1,a:5
[2/6]bb2lf:1,lp:1,rf:1,rp:1,rs:1,re:1,a:1
[3/0]cac24lf:12,lp:7,ls:5,rf:5,rp:1,rs:5,re:1,lprs:2,lsrs:4,a:1
[3/1]ccb16lf:8,ls:8,rf:7,rp:1,rs:7,re:1,lsrp:1,lsrs:7,a:11
[3/2]bac14lf:7,lp:7,a:9
[3/3]ccc14lf:14,rf:10,rp:4,a:14
[3/4]acc12lf:12,a:4
[3/5]acb5lf:3,ls:2,rf:1,rp:1,a:3
[3/6]aac4lf:2,lp:1,ls:1,rf:1,rp:1,rs:1,re:1,lprp:1,lprs:1,a:5

Considering [length 2 / frequency 0] ac=d.

Step 2

Rewriting system is complete. See ⟨a, b, c | ab=1, cac=bba⟩.