Morphocompletion for #7504 ⟨a, b, c | ab=1, bbaa=cc⟩

Solved by morph:3/0. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: roundsLimit

#Rule
1. ab ⇒ 1
2. aacba ⇒ aac
3. cc ⇒ bbaa
4. cbbaa ⇒ bbaac
5. acbba ⇒ baacb
6. aacacba ⇒ aacac
7. bbaacb ⇒ cbba
8. bacbb ⇒ cbb
9. baacbb ⇒ acbb
10. aacacacba ⇒ aacacac
11. aacacacacba ⇒ aacacacac
12. bacbcbb ⇒ cbcbb
13. bacbcbba ⇒ cbcbba
14. baacbcbb ⇒ acbcbb
15. aacacacacacba ⇒ aacacacacac
16. bacbcbcbb ⇒ cbcbcbb
17. baacbcbcbb ⇒ acbcbcbb
18. bacbcbcbcbb ⇒ cbcbcbcbb
19. baacbcbcbcbb ⇒ acbcbcbcbb
...

Collecting factors up to length 4 / frequency 7:

[2/0]ba34lf:18,lp:9,ls:7,rf:5,rp:1,rs:2,lsrp:1,lprs:1,lsrs:1,a:1
[2/1]cb32lf:30,lp:1,ls:1,rf:24,rp:6,rs:1,lsrp:1,a:2
[2/2]ac27lf:26,lp:1,rf:21,rp:4,rs:6,a:2
[2/3]bb21lf:12,lp:1,ls:8,rf:12,rp:2,rs:8,lsrs:8,a:1
[2/4]aa17lf:11,lp:5,ls:1,rf:8,rp:5,rs:1,lprp:5,a:1
[2/5]bc13lf:13,rf:13,a:14
[2/6]ca10lf:10,rf:10,a:11
[3/0]cbb20lf:11,lp:1,ls:8,rf:10,rp:2,rs:8,re:1,lsrp:1,lsrs:8,a:2
[3/1]acb18lf:16,lp:1,ls:1,rf:5,rp:4,rs:1,lprs:1,a:3
[3/2]aac15lf:10,lp:5,rf:7,rp:5,rs:2,re:1,lprp:5,lprs:1,a:2
[3/3]cbc13lf:13,rf:13,rp:4,a:14
[3/4]bcb13lf:13,rf:13,a:14
[3/5]baa11lf:6,lp:4,ls:1,rf:3,rp:1,rs:1,a:1
[3/6]cac10lf:10,rf:10,rs:4,a:11

Considering [length 3 / frequency 0] cbb=d.

Step 2

Rewriting system is complete. See ⟨a, b, c | ab=1, bbaa=cc⟩.