Morphocompletion for #7315 ⟨a, b, c | ab=1, aaca=ac⟩

Solved by morph:2/0. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: roundsLimit

#Rule
1. ab ⇒ 1
2. acba ⇒ ac
3. acbba ⇒ acb
4. acbbba ⇒ acbb
5. acbbbba ⇒ acbbb
6. aac ⇒ acb
7. accba ⇒ acc
8. accbba ⇒ accb
9. accbbba ⇒ accbb
10. acac ⇒ accb
11. acbc ⇒ acca
12. acbbc ⇒ accaa
13. acbbbc ⇒ accaaa
14. acccba ⇒ accc
15. acccbba ⇒ acccb
16. accac ⇒ acccb
17. accbc ⇒ accca
18. accbbc ⇒ acccaa
19. accccba ⇒ acccc
...

Collecting factors up to length 4 / frequency 7:

[2/0]ac40lf:20,lp:17,ls:3,rf:18,rp:18,rs:1,re:1,lprp:17,lsrp:12,lprs:1,a:2
[2/1]ba20lf:10,ls:10,a:4
[2/2]cb15lf:15,rf:9,rs:6,a:2
[2/3]bb14lf:14,rf:4,rs:3,a:7
[2/4]cc13lf:13,rf:20,rs:3,a:5
[2/5]bc10lf:5,ls:5,a:11
[2/6]ca2lf:2,rf:5,rs:2,a:5
[3/0]acc18lf:9,lp:9,rf:13,rp:13,rs:1,re:1,lprp:9,lprs:1,a:5
[3/1]acb14lf:7,lp:7,rf:4,rp:4,rs:2,re:2,lprp:3,lprs:1,a:2
[3/2]bba12lf:6,ls:6,a:7
[3/3]cbb9lf:9,rf:3,rs:2,a:7
[3/4]ccb8lf:8,rf:5,rs:4,a:5
[3/5]cba8lf:4,ls:4,a:4
[3/6]bbc6lf:3,ls:3,a:20

Considering [length 2 / frequency 0] ac=d.

Step 2

Rewriting system is complete. See ⟨a, b, c | ab=1, aaca=ac⟩.