Certificate for #6894 ⟨a, b, c | ab=1, abcca=c⟩

Back:⟨a, b, c | ab=1, abcca=c⟩

Completion settings:

[1] ab=1

Axiom: ab=1.

Defines rule #1.

Referenced by [2], [3].

[2] cca=c

Axiom: abcca=c.

Reduce LHS:

[1](ab)cca
⇒ cca

Defines rule #3.

Referenced by [3].

[3] cb=cc

Overlap of [2] cca=c with [1] ab=1:

cc a ab

Critical pair: cc=cb.

Flip LHS and RHS.

Defines rule #2.