| Back: | ⟨a, b, c | ab=1, abcaa=c⟩ |
|---|
Completion settings:
Axiom: ab=1.
Defines rule #1.
Axiom: abcaa=c.
Reduce LHS:
| [1] | (ab)caa |
| ⇒ caa |
Defines rule #3.
Referenced by [3].
Overlap of [2] caa=c with [1] ab=1:
Critical pair: ca=cb.
Flip LHS and RHS.
Defines rule #2.