Certificate for #6812 ⟨a, b, c | ab=1, aabcb=b⟩

Completion settings:

[1] ab=1

Axiom: ab=1.

Defines rule #1.

Referenced by [2].

[2] acb=b

Axiom: aabcb=b.

Reduce LHS:

[1]a(ab)cb
⇒ acb

Defines rule #2.