Certificate for #6682 ⟨a, b, c | aa=1, abcba=b⟩

Completion settings:

[1] aa=1

Axiom: aa=1.

Defines rule #3.

Referenced by [3], [4], [6].

[2] abcba=b

Axiom: abcba=b.

Referenced by [3], [4].

[3] bcba=ab

Overlap of [1] aa=1 with [2] abcba=b:

a a abcba

Critical pair: ab=bcba.

Flip LHS and RHS.

Referenced by [5].

[4] ba=abcb

Overlap of [2] abcba=b with [1] aa=1:

abcb a aa

Critical pair: abcb=ba.

Flip LHS and RHS.

Defines rule #1.

Referenced by [5].

[5] bcabcb=ab

Simplify [3] bcba=ab.

Reduce LHS:

[4]bc(ba)
⇒ bcabcb

Defines rule #2.

Referenced by [6].

[6] bcabcab=b

Overlap of [5] bcabcb=ab with [5] bcabcb=ab:

bcabc b bcabcb

Critical pair: bcabcab=abcabcb.

Reduce RHS:

[5]a(bcabcb)
[1]⇒ (aa)b
⇒ b

Defines rule #4.