Morphocompletion for #6154 ⟨a, b, c | aa=1, abaccb=1⟩

Solved by morph:2/0. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: roundsLimit

#Rule
1. aa ⇒ 1
2. cbab ⇒ babaca
3. babacc ⇒ 1
4. baccb ⇒ a
5. bacca ⇒ ccb
6. ccba ⇒ bacc
7. babacbacc ⇒ cba
8. babacbacbacc ⇒ cbacba
9. baccccb ⇒ cca
10. bacccca ⇒ ccccb
11. babacbacbacbacc ⇒ cbacbacba
12. baccccccb ⇒ cccca
13. bacccccca ⇒ ccccccb
14. baccccccccb ⇒ cccccca
15. bacccccccca ⇒ ccccccccb
16. baccccccccccb ⇒ cccccccca
17. bacccccccccca ⇒ ccccccccccb
18. baccccccccccccb ⇒ cccccccccca
19. bacccccccccccca ⇒ ccccccccccccb
...

Collecting factors up to length 4 / frequency 7:

[2/0]cc82lf:77,lp:1,ls:4,rf:62,rp:11,rs:1,lprs:1,a:2
[2/1]ba45lf:28,lp:16,ls:1,rf:9,rp:2,rs:3,lsrp:1,lprs:3,a:2
[2/2]ac22lf:22,rf:5,a:2
[2/3]cb21lf:14,lp:1,ls:6,rf:12,rp:3,rs:6,a:2
[2/4]ca12lf:6,ls:6,rf:6,rs:6,a:4
[2/5]ab6lf:5,ls:1,rf:1,a:9
[3/0]ccc60lf:60,rf:50,rp:9,a:6
[3/1]bac34lf:22,lp:12,rf:5,rp:1,a:2
[3/2]acc20lf:16,ls:4,rf:1,rs:1,a:2
[3/3]ccb14lf:7,lp:1,ls:6,rf:6,rp:1,rs:6,re:1,a:2
[3/4]cca12lf:6,ls:6,rf:5,rp:1,rs:5,re:1,a:4
[3/5]cba10lf:8,lp:1,ls:1,rf:6,rp:3,rs:3,re:1,a:7
[3/6]bab10lf:5,lp:4,ls:1,rf:1,rp:1,lsrp:1,a:9

Considering [length 2 / frequency 0] cc=d.

Step 2

Rewriting system is complete. See ⟨a, b, c | aa=1, abaccb=1⟩.