Morphocompletion for #6095 ⟨a, b, c | ab=c, bcc=ca⟩

Solved by morph:2/0. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: roundsLimit

#Rule
1. ab ⇒ c
2. bccb ⇒ cc
3. ca ⇒ bcc
4. acc ⇒ cccb
5. bcccc ⇒ ccccb
6. acbcc ⇒ cccba
7. ccccba ⇒ bcccbcc
8. ccccbba ⇒ bbcccbcc
9. ccccbbba ⇒ bbbcccbcc
10. ccccbbbba ⇒ bbbbcccbcc
11. ccccbbbbba ⇒ bbbbbcccbcc
12. acbcbcc ⇒ cccbaa
13. ccccbcba ⇒ bcbcccbcc
14. ccccbcbba ⇒ bcbbcccbcc
15. ccccbcbbba ⇒ bcbbbcccbcc
16. ccccbbcba ⇒ bbcbcccbcc
17. ccccbbcbba ⇒ bbcbbcccbcc
18. acbcbcbcc ⇒ cccbaaa
19. acbcbcbcbcc ⇒ cccbaaaa
20. acbbcccbcc ⇒ cccbcccbba
...

Collecting factors up to length 4 / frequency 7:

[2/0]cc59lf:42,lp:10,ls:7,rf:49,rp:8,rs:12,re:1,lsrp:7,lprs:10,a:1
[2/1]cb29lf:28,ls:1,rf:23,rs:2,a:2
[2/2]bc21lf:19,lp:2,rf:27,rp:5,a:1
[2/3]ba20lf:10,ls:10,rf:5,rs:2,a:5
[2/4]bb17lf:17,rf:17,rp:6,a:8
[2/5]ac12lf:6,lp:6,a:3
[2/6]aa0rf:6,rs:3,a:7
[3/0]ccc34lf:23,lp:10,ls:1,rf:19,rp:7,lsrp:1,a:3
[3/1]bcc15lf:8,lp:2,ls:5,rf:22,rp:2,rs:11,re:1,a:1
[3/2]cbc14lf:14,rf:13,a:5
[3/3]bba14lf:7,ls:7,rf:1,rs:1,a:8
[3/4]ccb13lf:12,ls:1,rf:18,rs:2,a:2
[3/5]bcb11lf:11,rf:5,rp:3,a:7
[3/6]acb10lf:5,lp:5,a:5

Considering [length 2 / frequency 0] cc=d.

Step 2

Rewriting system is complete. See ⟨a, b, c | ab=c, bcc=ca⟩.