Morphocompletion for #6073 ⟨a, b, c | ab=c, bac=cc⟩

Solved by morph:3/1. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: roundsLimit

#Rule
1. acc ⇒ cac
2. bac ⇒ cc
3. bcac ⇒ ccc
4. bccac ⇒ cccc
5. bcccac ⇒ ccccc
6. bccccac ⇒ cccccc
7. bcccccac ⇒ ccccccc
8. bccccccac ⇒ cccccccc
9. bcccccccac ⇒ ccccccccc
10. bccccccccac ⇒ cccccccccc
11. bcccccccccac ⇒ ccccccccccc
12. bccccccccccac ⇒ cccccccccccc
13. bcccccccccccac ⇒ ccccccccccccc
14. bccccccccccccac ⇒ cccccccccccccc
15. bcccccccccccccac ⇒ ccccccccccccccc
16. bccccccccccccccac ⇒ cccccccccccccccc
17. bcccccccccccccccac ⇒ ccccccccccccccccc
18. bccccccccccccccccac ⇒ cccccccccccccccccc
19. bcccccccccccccccccac ⇒ ccccccccccccccccccc
20. ab ⇒ c
...

Collecting factors up to length 4 / frequency 7:

[2/0]cc138lf:137,ls:1,rf:171,rp:18,rs:18,re:1,a:1
[2/1]ac38lf:19,lp:1,ls:18,rf:1,rs:1,lprs:10,a:1
[2/2]bc34lf:17,lp:17,a:3
[2/3]ca17lf:17,rf:1,rp:1,a:2
[2/4]ba2lf:1,lp:1,a:1
[3/0]ccc120lf:120,rf:153,rp:17,rs:17,re:1,a:3
[3/1]cac34lf:17,ls:17,rf:1,rp:1,rs:1,re:1,a:2
[3/2]bcc32lf:16,lp:16,a:4
[3/3]cca16lf:16,a:4
[3/4]bca2lf:1,lp:1,a:3

Considering [length 3 / frequency 1] cac=d.

Step 2

Rewriting system is complete. See ⟨a, b, c | ab=c, bac=cc⟩.