Morphocompletion for #6068 ⟨a, b, c | ab=c, bac=ba⟩

Solved by morph:2/1. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: roundsLimit

#Rule
1. ab ⇒ c
2. bac ⇒ ba
3. cac ⇒ ca
4. baac ⇒ baa
5. caac ⇒ caa
6. baaac ⇒ baaa
7. caaac ⇒ caaa
8. baaaac ⇒ baaaa
9. caaaac ⇒ caaaa
10. baaaaac ⇒ baaaaa
11. caaaaac ⇒ caaaaa
12. baaaaaac ⇒ baaaaaa
13. caaaaaac ⇒ caaaaaa
14. baaaaaaac ⇒ baaaaaaa
15. caaaaaaac ⇒ caaaaaaa
16. baaaaaaaac ⇒ baaaaaaaa
17. caaaaaaaac ⇒ caaaaaaaa
18. baaaaaaaaac ⇒ baaaaaaaaa
19. caaaaaaaaac ⇒ caaaaaaaaa
20. baaaaaaaaaac ⇒ baaaaaaaaaa
...

Collecting factors up to length 4 / frequency 7:

[2/0]aa81lf:81,rf:81,rs:17,a:3
[2/1]ac38lf:19,ls:19,a:1
[2/2]ba20lf:10,lp:10,rf:10,rp:10,rs:1,re:1,lprp:10,lprs:1,a:1
[2/3]ca18lf:9,lp:9,rf:9,rp:9,rs:1,re:1,lprp:9,lprs:1,a:2
[3/0]aaa64lf:64,rf:64,rs:15,a:5
[3/1]aac34lf:17,ls:17,a:3
[3/2]baa18lf:9,lp:9,rf:9,rp:9,rs:1,re:1,lprp:9,lprs:1,a:3
[3/3]caa16lf:8,lp:8,rf:8,rp:8,rs:1,re:1,lprp:8,lprs:1,a:4

Considering [length 2 / frequency 1] ac=d.

Step 2

Rewriting system is complete. See ⟨a, b, c | ab=c, bac=ba⟩.