Morphocompletion for #6034 ⟨a, b, c | ab=c, aca=ac⟩

Solved by morph:2/1. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: roundsLimit

#Rule
1. ab ⇒ c
2. aca ⇒ ac
3. acc ⇒ acb
4. acba ⇒ acb
5. acbc ⇒ acbb
6. acbba ⇒ acbb
7. acbbc ⇒ acbbb
8. acbbba ⇒ acbbb
9. acbbbc ⇒ acbbbb
10. acbbbba ⇒ acbbbb
11. acbbbbc ⇒ acbbbbb
12. acbbbbba ⇒ acbbbbb
13. acbbbbbc ⇒ acbbbbbb
14. acbbbbbba ⇒ acbbbbbb
15. acbbbbbbc ⇒ acbbbbbbb
16. acbbbbbbba ⇒ acbbbbbbb
17. acbbbbbbbc ⇒ acbbbbbbbb
18. acbbbbbbbba ⇒ acbbbbbbbb
19. acbbbbbbbbc ⇒ acbbbbbbbbb
20. acbbbbbbbbba ⇒ acbbbbbbbbb
...

Collecting factors up to length 4 / frequency 7:

[2/0]bb64lf:64,rf:72,rs:16,a:4
[2/1]ac38lf:19,lp:19,rf:19,rp:19,rs:1,re:1,lprp:19,lprs:1,a:1
[2/2]ba18lf:9,ls:9,a:3
[2/3]cb17lf:17,rf:18,rs:2,a:2
[2/4]bc16lf:8,ls:8,a:4
[2/5]cc2lf:1,ls:1,a:2
[2/6]ca2lf:1,ls:1,a:1
[3/0]bbb49lf:49,rf:56,rs:14,a:6
[3/1]acb34lf:17,lp:17,rf:18,rp:18,rs:2,re:2,lprp:17,lprs:1,a:2
[3/2]bba16lf:8,ls:8,a:5
[3/3]cbb15lf:15,rf:16,rs:2,a:4
[3/4]bbc14lf:7,ls:7,a:6
[3/5]cbc2lf:1,ls:1,a:4
[3/6]cba2lf:1,ls:1,a:3

Considering [length 2 / frequency 1] ac=d.

Step 2

Rewriting system is complete. See ⟨a, b, c | ab=c, aca=ac⟩.