Certificate for #5919 ⟨a, b, c | ab=a, cab=bb⟩

Back:⟨a, b, c | ab=a, cab=bb⟩

Completion settings:

[1] ab=a

Axiom: ab=a.

Defines rule #1.

Referenced by [2], [3].

[2] ca=bb

Axiom: cab=bb.

Reduce LHS:

[1]c(ab)
⇒ ca

Defines rule #2.

Referenced by [3].

[3] bbb=bb

Overlap of [2] ca=bb with [1] ab=a:

c a ab

Critical pair: ca=bbb.

Reduce LHS:

[2](ca)
⇒ bb

Flip LHS and RHS.

Defines rule #3.