#56 ⟨a, b, c | aaa=1, bac=1⟩

Properties

Sum of relation sides is 6
Infinite non-cancellative non-commutative monoid
Element ba² has infinite order
Not left cancellative, because left multiplication by b is not injective:
- b ⋅ acb = b and b ⋅ 1 = b, however acb ≠ 1
Not right cancellative, because right multiplication by ac is not injective:
- acb ⋅ ac = ac and 1 ⋅ ac = ac, however acb ≠ 1

Format:	Pretty Plain
Word:
	Enter a word above to compute its normal form. Tips: Lowercase letters stand for generators. Spaces are ignored. Numbers repeat the previous letter, e.g. `b90`.
Strategy:	Leftmost Rightmost
Result:	1 1

#	Rule	Proof
1.	a³ ⇒ 1	[1]
2.	bac ⇒ 1	[2]

# abc:aaa=1,bac=1 abc - -
aaa=1
bac=1

The mapping is from the listed presentation's alphabet to the current rewriting system's alphabet.

1 total

Σ	#	Presentation	Mapping
8	4112	⟨a, b, c \| aaa=1, abac=a⟩	φ(a) = a, φ(b) = b, φ(c) = c