#5569 ⟨a, b, c | ab=c, bacc=b⟩

Properties

Sum of relation sides is 8
Infinite non-cancellative non-commutative monoid
Element a has infinite order
Not left cancellative, because left multiplication by b is not injective:
- b ⋅ a(ab)² = b and b ⋅ 1 = b, however a(ab)² ≠ 1
Not right cancellative, because right multiplication by b is not injective:
- ba²ba ⋅ b = b and 1 ⋅ b = b, however ba²ba ≠ 1

Format:	Pretty Plain
Word:
	Enter a word above to compute its normal form. Tips: Lowercase letters stand for generators. Spaces are ignored. Numbers repeat the previous letter, e.g. `b90`.
Strategy:	Leftmost Rightmost
Result:	1 1

Reduction order:
- Left-to-right recursive path with deg(a) = deg(b) = 0, a < b; deg(c) = 1
Certificate: derivations of all rewriting rules from the defining relations.

#	Rule	Proof
1.	ba(ab)² ⇒ b	[2]
2.	c ⇒ ab	[1]

# abc:ab=c,bacc=b ab/c - -
baabab=b
c=ab

The mapping is from the listed presentation's alphabet to the current rewriting system's alphabet.

1 total

Σ	#	Presentation	Mapping
8	5586	⟨a, b, c \| ab=c, bcac=b⟩	φ(a) = a, φ(b) = b, φ(c) = ab