Certificate for #5568 ⟨a, b, c | ab=c, bacc=a⟩

Completion settings:

[1] c=ab

Axiom: ab=c.

Flip LHS and RHS.

Defines rule #3.

Referenced by [2].

[2] baabab=a

Axiom: bacc=a.

Reduce LHS:

[1]ba(c)c
[1]⇒ baab(c)
⇒ baabab

Defines rule #1.

Referenced by [3].

[3] aaabab=baabaa

Overlap of [2] baabab=a with [2] baabab=a:

baaba b baabab

Critical pair: baabaa=aaabab.

Flip LHS and RHS.

Defines rule #2.