Morphocompletion for #5567 ⟨a, b, c | ab=c, baca=c⟩

Solved by morph:2/0. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: roundsLimit

#Rule
1. ab ⇒ c
2. bacc ⇒ cb
3. acb ⇒ cacc
4. caca ⇒ ac
5. baca ⇒ c
6. caac ⇒ acca
7. baac ⇒ cca
8. caccacc ⇒ accb
9. baaac ⇒ caccaa
10. ccaaac ⇒ acccaa
11. bcaaac ⇒ cccaa
12. caaacc ⇒ aaccca
13. acaccaa ⇒ caaac
14. bcaaaac ⇒ cacccaaa
15. cbaaaac ⇒ accbaaa
16. bbaaaac ⇒ ccbaaa
17. cbbaaaac ⇒ cccbaaa
18. baaaaccc ⇒ aacccca
19. baaaaccb ⇒ aaccbac
20. accaccaaa ⇒ baaaac
...

Collecting factors up to length 4 / frequency 7:

[2/0]ac34lf:22,lp:3,ls:9,rf:14,rp:5,rs:4,re:1,lsrp:3,lprs:2,a:1
[2/1]aa33lf:31,ls:2,rf:19,rp:3,rs:7,a:5
[2/2]ca20lf:14,lp:4,ls:2,rf:12,rp:4,rs:4,lprs:2,a:1
[2/3]cc16lf:11,lp:1,ls:4,rf:21,rp:4,rs:1,a:3
[2/4]ba15lf:9,lp:6,rf:5,rp:1,a:1
[2/5]cb8lf:4,lp:2,ls:2,rf:6,rp:1,rs:2,re:1,a:3
[2/6]bc4lf:2,lp:2,a:23
[3/0]aac21lf:12,ls:9,rf:5,rp:3,rs:2,a:5
[3/1]aaa18lf:17,ls:1,rf:7,rs:4,a:8
[3/2]acc13lf:9,lp:1,ls:3,rf:10,rp:4,rs:1,lsrp:1,a:3
[3/3]baa11lf:7,lp:4,rf:4,rp:1,a:5
[3/4]caa10lf:7,lp:2,ls:1,rf:5,rp:1,rs:3,lsrp:1,a:6
[3/5]cac7lf:5,lp:2,rf:3,rp:3,a:2
[3/6]aca6lf:3,lp:1,ls:2,a:1

Considering [length 2 / frequency 0] ac=d.

Step 2

Rewriting system is complete. See ⟨a, b, c | ab=c, baca=c⟩.