Certificate for #5396 ⟨a, b, c | ab=a, bcca=b⟩

Back:⟨a, b, c | ab=a, bcca=b⟩

Completion settings:

[1] ab=a

Axiom: ab=a.

Defines rule #1.

Referenced by [3], [4].

[2] bcca=b

Axiom: bcca=b.

Defines rule #4.

Referenced by [3], [4].

[3] acca=a

Overlap of [1] ab=a with [2] bcca=b:

a b bcca

Critical pair: ab=acca.

Reduce LHS:

[1](ab)
⇒ a

Flip LHS and RHS.

Defines rule #3.

[4] bb=b

Overlap of [2] bcca=b with [1] ab=a:

bcc a ab

Critical pair: bcca=bb.

Reduce LHS:

[2](bcca)
⇒ b

Flip LHS and RHS.

Defines rule #2.