| Back: | ⟨a, b, c | ab=a, bcaa=b⟩ |
|---|
Completion settings:
Axiom: ab=a.
Defines rule #1.
Axiom: bcaa=b.
Defines rule #4.
Overlap of [1] ab=a with [2] bcaa=b:
Critical pair: ab=acaa.
Reduce LHS:
| [1] | (ab) |
| ⇒ a |
Flip LHS and RHS.
Defines rule #3.
Overlap of [2] bcaa=b with [1] ab=a:
Critical pair: bcaa=bb.
Reduce LHS:
| [2] | (bcaa) |
| ⇒ b |
Flip LHS and RHS.
Defines rule #2.