Certificate for #4862 ⟨a, b, c | ab=a, bbbbc=1⟩

Back:⟨a, b, c | ab=a, bbbbc=1⟩

Completion settings:

[1] ab=a

Axiom: ab=a.

Defines rule #1.

Referenced by [3].

[2] bbbbc=1

Axiom: bbbbc=1.

Defines rule #3.

Referenced by [3].

[3] ac=a

Overlap of [1] ab=a with [2] bbbbc=1:

a b bbbbc

Critical pair: a=abbbc.

Reduce RHS:

[1](ab)bbc
[1]⇒ (ab)bc
[1]⇒ (ab)c
⇒ ac

Flip LHS and RHS.

Defines rule #2.