Certificate for #4856 ⟨a, b, c | ab=a, bbaac=1⟩

Back:⟨a, b, c | ab=a, bbaac=1⟩

Completion settings:

[1] ab=a

Axiom: ab=a.

Defines rule #1.

Referenced by [3].

[2] bbaac=1

Axiom: bbaac=1.

Defines rule #3.

Referenced by [3].

[3] aaac=a

Overlap of [1] ab=a with [2] bbaac=1:

a b bbaac

Critical pair: a=abaac.

Reduce RHS:

[1](ab)aac
⇒ aaac

Flip LHS and RHS.

Defines rule #2.