Certificate for #460 ⟨a, b, c | ba=ab, abc=1⟩

Completion settings:

[1] ab=ba

Axiom: ba=ab.

Flip LHS and RHS.

Referenced by [2], [4].

[2] bac=1

Axiom: abc=1.

Reduce LHS:

[1](ab)c
⇒ bac

Referenced by [5].

[3] ba=d

Axiom: ba=d.

Defines rule #3.

Referenced by [4], [5], [6], [7].

[4] ab=d

Simplify [1] ab=ba.

Reduce RHS:

[3](ba)
⇒ d

Defines rule #4.

Referenced by [6], [7].

[5] dc=1

Overlap of [2] bac=1 with [3] ba=d:

bac ba

Critical pair: dc=1.

Defines rule #2.

[6] da=ad

Overlap of [4] ab=d with [3] ba=d:

a b ba

Critical pair: ad=da.

Flip LHS and RHS.

Defines rule #1.

[7] db=bd

Overlap of [3] ba=d with [4] ab=d:

b a ab

Critical pair: bd=db.

Flip LHS and RHS.

Defines rule #5.