Morphocompletion for #4476 ⟨a, b, c | aba=1, cbcc=b⟩

Solved by morph:2/6. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: roundsLimit

#Rule
1. ccaac ⇒ aa
2. ccaaaa ⇒ aacaac
3. baa ⇒ 1
4. bccaac ⇒ 1
5. baccaac ⇒ a
6. ab ⇒ ba
7. cbcc ⇒ b
8. cbcaa ⇒ bcaac
9. aacb ⇒ bccccaa
10. aacbc ⇒ bccaa
11. caacb ⇒ bccaa
12. bbccaa ⇒ cbc
13. bbaccaa ⇒ acbc
14. bbccccaa ⇒ cb
15. bcaacb ⇒ cbc
16. bacaacb ⇒ acbc
17. bcaaccb ⇒ ccbc
18. cbb ⇒ bbcccc
19. cbcb ⇒ bbcc
...

Collecting factors up to length 4 / frequency 7:

[2/0]aa25lf:17,lp:2,ls:6,rf:7,rp:2,rs:4,re:1,lsrp:1,lprs:2,a:3
[2/1]cb21lf:11,lp:4,ls:6,rf:6,rp:3,rs:1,re:1,lsrp:1,a:1
[2/2]ac15lf:12,ls:3,rf:5,rp:2,rs:2,a:7
[2/3]cc14lf:11,lp:2,ls:1,rf:10,rp:1,rs:2,a:1
[2/4]bc13lf:9,lp:3,ls:1,rf:11,rp:4,rs:5,lsrp:1,lprs:2,a:1
[2/5]ca13lf:12,lp:1,rf:5,a:6
[2/6]bb8lf:4,lp:3,ls:1,rf:2,rp:2,lsrp:1,a:4
[3/0]caa17lf:12,lp:1,ls:4,rf:5,rs:3,lprs:1,a:6
[3/1]aac14lf:9,lp:2,ls:3,rf:3,rp:1,rs:2,a:12
[3/2]acb9lf:5,ls:4,rf:2,rp:2,lsrp:1,a:7
[3/3]cca9lf:7,lp:2,rf:3,a:6
[3/4]cbc8lf:4,lp:3,ls:1,rf:5,rp:2,rs:5,re:2,a:1
[3/5]bcc6lf:4,lp:1,ls:1,rf:5,rp:3,rs:1,a:1
[3/6]bca5lf:3,lp:2,rf:1,rp:1,a:20

Considering [length 2 / frequency 6] bb=d.

Step 2

Rewriting system is complete. See ⟨a, b, c | aba=1, cbcc=b⟩.