Morphocompletion for #4260 ⟨a, b, c | aab=1, bcaa=c⟩

Solved by morph:2/0. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: roundsLimit

#Rule
1. bc ⇒ cb
2. cab ⇒ cba
3. aac ⇒ caa
4. aab ⇒ 1
5. cbab ⇒ cbba
6. cbaa ⇒ c
7. cacb ⇒ cbac
8. cbbab ⇒ cbbba
9. cbbaa ⇒ cb
10. cbacb ⇒ cbbac
11. caccb ⇒ cbacc
12. cbbbab ⇒ cbbbba
13. cbbbaa ⇒ cbb
14. cbbacb ⇒ cbbbac
15. cbaccb ⇒ cbbacc
16. cbacaa ⇒ cac
17. cbbbbaa ⇒ cbbb
18. cbbacaa ⇒ cbac
19. cbaccaa ⇒ cacc
...

Collecting factors up to length 4 / frequency 7:

[2/0]cb36lf:18,lp:13,ls:5,rf:14,rp:14,rs:2,re:2,lprp:10,lsrp:5,lprs:1,a:3
[2/1]aa18lf:9,lp:2,ls:7,rf:1,rs:1,lprs:10
[2/2]ba13lf:13,rf:10,rs:4,a:4
[2/3]bb11lf:11,rf:13,rs:2,a:6
[2/4]ab10lf:5,ls:5
[2/5]ac10lf:9,ls:1,rf:8,rs:5,a:2
[2/6]ca9lf:6,lp:3,rf:3,rp:3,a:2
[3/0]cbb14lf:7,lp:7,rf:8,rp:8,rs:1,re:1,lprp:5,lprs:1,a:6
[3/1]cba12lf:6,lp:6,rf:4,rp:4,rs:1,re:1,a:4
[3/2]baa8lf:4,ls:4,a:5
[3/3]bba7lf:7,rf:6,rs:3,a:6
[3/4]acb6lf:3,ls:3,a:8
[3/5]bab6lf:3,ls:3,a:7
[3/6]bac6lf:6,rf:6,rs:4,a:8

Considering [length 2 / frequency 0] cb=d.

Step 2

Rewriting system is complete. See ⟨a, b, c | aab=1, bcaa=c⟩.