Morphocompletion for #417 ⟨a, b, c | abc=b, cba=1⟩

Solved by morph:2/0. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: roundsLimit

#Rule
1. bba ⇒ ab
2. bc ⇒ cbb
3. acbb ⇒ b
4. bac ⇒ acb
5. cba ⇒ 1
6. acab ⇒ ba
7. accbbbb ⇒ cbb
8. cacb ⇒ c
9. acaab ⇒ baba
10. accabb ⇒ cab
11. caccbb ⇒ cc
12. ccac ⇒ caccb
13. caccab ⇒ cca
...

Collecting factors up to length 4 / frequency 7:

[2/0]ac17lf:10,lp:5,ls:2,rf:2,rp:1,lsrp:10,a:4
[2/1]bb12lf:7,lp:1,ls:4,rf:2,rs:2,lsrs:1,a:2
[2/2]ca11lf:8,lp:3,rf:3,rp:2,rs:1,lprs:1,a:5
[2/3]cb7lf:5,lp:1,ls:1,rf:4,rp:2,rs:2,a:1
[2/4]ab7lf:4,ls:3,rf:3,rp:1,rs:2,re:1,a:2
[2/5]cc6lf:5,lp:1,rf:3,rp:2,rs:1,re:1,a:6
[2/6]ba6lf:3,lp:1,ls:2,rf:3,rp:2,rs:2,re:1,a:1
[3/0]cac8lf:4,lp:3,ls:1,rf:1,rp:1,lsrp:1,a:9
[3/1]acc6lf:4,lp:2,rf:1,a:6
[3/2]cab5lf:3,ls:2,rf:1,rp:1,rs:1,re:1,a:5
[3/3]cbb5lf:3,ls:2,rf:2,rp:2,rs:2,re:2,a:3
[3/4]cca4lf:3,lp:1,rf:1,rp:1,rs:1,re:1,a:12
[3/5]aca4lf:2,lp:2,a:5
[3/6]acb4lf:2,lp:1,ls:1,rf:1,rp:1,rs:1,re:1,a:4

Considering [length 2 / frequency 0] ac=d.

Step 2

Rewriting system is complete. See ⟨a, b, c | abc=b, cba=1⟩.