Certificate for #417 ⟨a, b, c | abc=b, cba=1⟩

Completion settings:

[1] abc=b

Axiom: abc=b.

Referenced by [6], [7], [8], [9].

[2] cba=1

Axiom: cba=1.

Defines rule #8.

Referenced by [4], [5], [6], [8], [13], [16].

[3] ac=d

Axiom: ac=d.

Defines rule #7.

Referenced by [4], [5], [15].

[4] cbd=c

Overlap of [2] cba=1 with [3] ac=d:

cb a ac

Critical pair: cbd=c.

Referenced by [7].

[5] dba=a

Overlap of [3] ac=d with [2] cba=1:

a c cba

Critical pair: a=dba.

Flip LHS and RHS.

Referenced by [9].

[6] bba=ab

Overlap of [1] abc=b with [2] cba=1:

ab c cba

Critical pair: ab=bba.

Flip LHS and RHS.

Defines rule #4.

Referenced by [11].

[7] bbd=b

Overlap of [1] abc=b with [4] cbd=c:

ab c cbd

Critical pair: abc=bbd.

Reduce LHS:

[1](abc)
⇒ b

Flip LHS and RHS.

Referenced by [10], [11], [12].

[8] bc=cbb

Overlap of [2] cba=1 with [1] abc=b:

cb a abc

Critical pair: cbb=bc.

Flip LHS and RHS.

Defines rule #5.

[9] dbb=b

Overlap of [5] dba=a with [1] abc=b:

db a abc

Critical pair: dbb=abc.

Reduce RHS:

[1](abc)
⇒ b

Referenced by [10].

[10] db=bd

Overlap of [9] dbb=b with [7] bbd=b:

d bb bbd

Critical pair: db=bd.

Referenced by [11], [17].

[11] dab=ba

Overlap of [10] db=bd with [6] bba=ab:

d b bba

Critical pair: dab=bdba.

Reduce RHS:

[10]b(db)a
[7]⇒ (bbd)a
⇒ ba

Referenced by [12], [14].

[12] babd=ba

Overlap of [11] dab=ba with [7] bbd=b:

da b bbd

Critical pair: dab=babd.

Reduce LHS:

[11](dab)
⇒ ba

Flip LHS and RHS.

Referenced by [13].

[13] bd=1

Overlap of [2] cba=1 with [12] babd=ba:

c ba babd

Critical pair: cba=bd.

Reduce LHS:

[2](cba)
⇒ 1

Flip LHS and RHS.

Defines rule #1.

Referenced by [14], [17].

[14] da=bad

Overlap of [11] dab=ba with [13] bd=1:

da b bd

Critical pair: da=bad.

Defines rule #3.

Referenced by [15].

[15] badc=dd

Overlap of [14] da=bad with [3] ac=d:

d a ac

Critical pair: dd=badc.

Flip LHS and RHS.

Referenced by [16].

[16] dc=cdd

Overlap of [2] cba=1 with [15] badc=dd:

c ba badc

Critical pair: cdd=dc.

Flip LHS and RHS.

Defines rule #6.

[17] db=1

Simplify [10] db=bd.

Reduce RHS:

[13](bd)
⇒ 1

Defines rule #2.