Morphocompletion for #358 ⟨a, b, c | aba=b, acb=1⟩

Solved by morph:2/0. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: roundsLimit

#Rule
1. bba ⇒ abb
2. cbb ⇒ ba
3. bcb ⇒ ab
4. aba ⇒ b
5. acb ⇒ 1
6. cabb ⇒ baa
7. cba ⇒ 1
8. bcab ⇒ aab
9. acab ⇒ cb
10. caabb ⇒ baaa
11. bcaab ⇒ aaab
12. acaab ⇒ cab
13. caaabb ⇒ baaaa
14. bcaaab ⇒ aaaab
15. acaaab ⇒ caab
16. caaaabb ⇒ baaaaa
17. bcaaaab ⇒ aaaaab
18. acaaaab ⇒ caaab
19. acaaaaab ⇒ caaaab
...

Collecting factors up to length 4 / frequency 7:

[2/0]ab24lf:14,lp:1,ls:9,rf:10,rp:2,rs:9,re:1,lsrs:8
[2/1]aa22lf:22,rf:26,rp:4,rs:4,a:5
[2/2]ca17lf:13,lp:4,rf:4,rp:4,a:4
[2/3]ac12lf:6,lp:6,a:1
[2/4]bb12lf:6,lp:1,ls:5,rf:1,rs:1,lprs:10,a:2
[2/5]bc10lf:5,lp:5,a:3
[2/6]cb8lf:4,lp:2,ls:2,rf:1,rp:1,rs:1,re:1,a:1
[3/0]aab17lf:10,ls:7,rf:7,rp:1,rs:7,re:1,lsrs:6,a:5
[3/1]caa13lf:10,lp:3,rf:3,rp:3,a:14
[3/2]aaa12lf:12,rf:15,rp:3,rs:3,a:15
[3/3]aca10lf:5,lp:5,a:4
[3/4]bca8lf:4,lp:4,a:5
[3/5]abb8lf:4,ls:4,rf:1,rp:1,rs:1,re:1,a:2
[3/6]cab6lf:3,lp:1,ls:2,rf:1,rp:1,rs:1,re:1,a:4

Considering [length 2 / frequency 0] ab=d.

Step 2

Rewriting system is complete. See ⟨a, b, c | aba=b, acb=1⟩.