Morphocompletion for #3490 ⟨a, b, c | bb=aa, acb=c⟩

Solved by morph:3/0. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: roundsLimit

#Rule
1. aab ⇒ baa
2. bb ⇒ aa
3. acaa ⇒ cb
4. acb ⇒ c
5. acabaa ⇒ cbab
6. acababaa ⇒ cbabab
7. acabababaa ⇒ cbababab
8. acababababaa ⇒ cbabababab
9. acabababababaa ⇒ cbababababab
10. acc ⇒ cbcaa
11. acac ⇒ cbcb
12. acabc ⇒ cbabcaa
13. acabac ⇒ cbabcb
14. acababc ⇒ cbababcaa
15. acababac ⇒ cbababcb
16. acabababc ⇒ cbabababcaa
17. acabababac ⇒ cbabababcb
18. acababababc ⇒ cbababababcaa
19. acababababac ⇒ cbababababcb
20. acabababababac ⇒ cbabababababcb
...

Collecting factors up to length 4 / frequency 7:

[2/0]ac48lf:24,lp:18,ls:6,a:1
[2/1]ab42lf:41,ls:1,rf:40,rs:5,a:2
[2/2]ba36lf:36,rf:41,rp:1,a:2
[2/3]ca16lf:16,rf:5,a:3
[2/4]aa14lf:7,lp:1,ls:6,rf:7,rp:1,rs:7,re:1,lprs:10
[2/5]bc8lf:4,ls:4,rf:11,a:4
[2/6]cc2lf:1,ls:1,a:6
[3/0]aba36lf:36,rf:26,a:5
[3/1]aca32lf:16,lp:16,a:3
[3/2]bab26lf:26,rf:40,rs:5,a:5
[3/3]cab14lf:14,a:5
[3/4]bac10lf:5,ls:5,a:7
[3/5]baa10lf:5,ls:5,rf:1,rp:1,rs:1,re:1,a:2
[3/6]abc8lf:4,ls:4,rf:9,a:7

Considering [length 3 / frequency 0] aba=d.

Step 2

Rewriting system is complete. See ⟨a, b, c | bb=aa, acb=c⟩.