Morphocompletion for #3488 ⟨a, b, c | bb=aa, aca=c⟩

Solved by morph:3/2. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: roundsLimit

#Rule
1. aab ⇒ baa
2. bb ⇒ aa
3. aca ⇒ c
4. acbaa ⇒ cab
5. acbabaa ⇒ cabab
6. acbababaa ⇒ cababab
7. acbabababaa ⇒ cabababab
8. acbababababaa ⇒ cababababab
9. acbabababababaa ⇒ cabababababab
10. acc ⇒ cca
11. acbc ⇒ cabcaa
12. acbac ⇒ cabca
13. acbabc ⇒ cababcaa
14. acbabac ⇒ cababca
15. acbababc ⇒ cabababcaa
16. acbababac ⇒ cabababca
17. acbabababc ⇒ cababababcaa
18. acbabababac ⇒ cababababca
19. acbababababc ⇒ cabababababcaa
20. acbababababac ⇒ cabababababca
...

Collecting factors up to length 4 / frequency 7:

[2/0]ac46lf:23,lp:18,ls:5,a:1
[2/1]ba46lf:46,rf:36,rp:1,a:2
[2/2]ab37lf:36,ls:1,rf:51,rs:6,a:2
[2/3]cb16lf:16,a:4
[2/4]aa14lf:7,lp:1,ls:6,rf:7,rp:1,rs:7,re:1,lprs:10
[2/5]bc10lf:5,ls:5,rf:10,a:5
[2/6]cc2lf:1,ls:1,rf:1,rp:1,lsrp:10,a:3
[3/0]bab35lf:35,rf:35,rs:5,a:6
[3/1]acb32lf:16,lp:16,a:4
[3/2]aba31lf:31,rf:35,a:6
[3/3]cba15lf:15,a:4
[3/4]baa12lf:6,ls:6,rf:1,rp:1,rs:1,re:1,a:2
[3/5]bac10lf:5,ls:5,a:5
[3/6]abc8lf:4,ls:4,rf:10,a:5

Considering [length 3 / frequency 2] aba=d.

Step 2

Rewriting system is complete. See ⟨a, b, c | bb=aa, aca=c⟩.