Morphocompletion for #3473 ⟨a, b, c | ba=ac, cab=b⟩

Solved by morph:3/1. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: roundsLimit

#Rule
1. ac ⇒ ba
2. cab ⇒ b
3. caab ⇒ ab
4. baab ⇒ ab
5. caaab ⇒ aab
6. baaab ⇒ aab
7. caaaab ⇒ aaab
8. baaaab ⇒ aaab
9. caaaaab ⇒ aaaab
10. baaaaab ⇒ aaaab
11. caaaaaab ⇒ aaaaab
12. baaaaaab ⇒ aaaaab
13. caaaaaaab ⇒ aaaaaab
14. baaaaaaab ⇒ aaaaaab
15. caaaaaaaab ⇒ aaaaaaab
16. baaaaaaaab ⇒ aaaaaaab
17. caaaaaaaaab ⇒ aaaaaaaab
18. baaaaaaaaab ⇒ aaaaaaaab
19. caaaaaaaaaab ⇒ aaaaaaaaab
20. baaaaaaaaaab ⇒ aaaaaaaaab
...

Collecting factors up to length 4 / frequency 7:

[2/0]aa90lf:90,rf:72,rp:16,a:2
[2/1]ab38lf:19,ls:19,rf:18,rp:2,rs:18,re:2,lsrp:2,lsrs:18,a:1
[2/2]ca20lf:10,lp:10,a:1
[2/3]ba18lf:9,lp:9,rf:1,rp:1,rs:1,re:1
[3/0]aaa72lf:72,rf:56,rp:14,a:4
[3/1]aab36lf:18,ls:18,rf:16,rp:2,rs:16,re:2,lsrp:2,lsrs:16,a:2
[3/2]baa18lf:9,lp:9,a:2
[3/3]caa18lf:9,lp:9,a:3

Considering [length 3 / frequency 1] aab=d.

Step 2

Rewriting system is complete. See ⟨a, b, c | ba=ac, cab=b⟩.