| Back: | ⟨a, b, c | ba=ac, aac=b⟩ |
|---|
Completion settings:
Axiom: ba=ac.
Flip LHS and RHS.
Defines rule #3.
Axiom: aac=b.
Reduce LHS:
| [1] | a(ac) |
| ⇒ aba |
Defines rule #1.
Overlap of [2] aba=b with [2] aba=b:
Critical pair: abb=bba.
Flip LHS and RHS.
Defines rule #2.
Referenced by [4].
Overlap of [2] aba=b with [1] ac=ba:
Critical pair: abba=bc.
Reduce LHS:
| [3] | a(bba) |
| ⇒ aabb |
Flip LHS and RHS.
Defines rule #4.