Certificate for #3255 ⟨a, b, c | bb=aa, acca=1⟩

Completion settings:

[1] bb=aa

Axiom: bb=aa.

Referenced by [4].

[2] acca=1

Axiom: acca=1.

Referenced by [7], [8], [9], [10], [12].

[3] aa=d

Axiom: aa=d.

Defines rule #7.

Referenced by [4], [5], [8], [9].

[4] bb=d

Simplify [1] bb=aa.

Reduce RHS:

[3](aa)
⇒ d

Defines rule #8.

Referenced by [6].

[5] da=ad

Overlap of [3] aa=d with [3] aa=d:

a a aa

Critical pair: ad=da.

Flip LHS and RHS.

Defines rule #3.

Referenced by [9].

[6] db=bd

Overlap of [4] bb=d with [4] bb=d:

b b bb

Critical pair: bd=db.

Flip LHS and RHS.

Defines rule #5.

Referenced by [11].

[7] cca=acc

Overlap of [2] acca=1 with [2] acca=1:

acc a acca

Critical pair: acc=cca.

Flip LHS and RHS.

Defines rule #4.

Referenced by [9].

[8] accd=a

Overlap of [2] acca=1 with [3] aa=d:

acc a aa

Critical pair: accd=a.

Referenced by [10].

[9] adcc=a

Overlap of [3] aa=d with [2] acca=1:

a a acca

Critical pair: a=dcca.

Reduce RHS:

[7]d(cca)
[5]⇒ (da)cc
⇒ adcc

Flip LHS and RHS.

Referenced by [12].

[10] ccd=1

Overlap of [2] acca=1 with [8] accd=a:

acc a accd

Critical pair: acca=ccd.

Reduce LHS:

[2](acca)
⇒ 1

Flip LHS and RHS.

Defines rule #2.

Referenced by [11], [13], [15].

[11] ccbd=b

Overlap of [10] ccd=1 with [6] db=bd:

cc d db

Critical pair: ccbd=b.

Referenced by [14].

[12] dcc=1

Overlap of [2] acca=1 with [9] adcc=a:

acc a adcc

Critical pair: acca=dcc.

Reduce LHS:

[2](acca)
⇒ 1

Flip LHS and RHS.

Referenced by [13].

[13] dc=cd

Overlap of [12] dcc=1 with [10] ccd=1:

dc c ccd

Critical pair: dc=cd.

Defines rule #1.

Referenced by [14], [15].

[14] ccbcd=bc

Overlap of [11] ccbd=b with [13] dc=cd:

ccb d dc

Critical pair: ccbcd=bc.

Referenced by [15].

[15] ccb=bcc

Overlap of [14] ccbcd=bc with [13] dc=cd:

ccbc d dc

Critical pair: ccbccd=bcc.

Reduce LHS:

[10]ccb(ccd)
⇒ ccb

Defines rule #6.