#3157 ⟨a, b, c | ac=ab, babc=1⟩

Properties

Sum of relation sides is 8
Infinite non-cancellative non-commutative monoid
Element a has infinite order
Not left cancellative, because left multiplication by a is not injective:
- a ⋅ c = ab and a ⋅ b = ab, however c ≠ b
Not right cancellative, because right multiplication by abc is not injective:
- abcb ⋅ abc = abc and 1 ⋅ abc = abc, however abcb ≠ 1

Format:	Pretty Plain
Word:
	Enter a word above to compute its normal form. Tips: Lowercase letters stand for generators. Spaces are ignored. Numbers repeat the previous letter, e.g. `b90`.
Strategy:	Leftmost Rightmost
Result:	1 1

#	Rule	Proof
1.	ac ⇒ ab	[1]
2.	babc ⇒ 1	[2]

# abc:ac=ab,babc=1 abc - -
ac=ab
babc=1

The mapping is from the listed presentation's alphabet to the current rewriting system's alphabet.

1 total

Σ	#	Presentation	Mapping
8	3160	⟨a, b, c \| ac=ab, bacc=1⟩	φ(a) = a, φ(b) = b, φ(c) = c