Certificate for #3109 ⟨a, b, c | ab=aa, bccb=1⟩

Completion settings:

[1] ab=aa

Axiom: ab=aa.

Defines rule #9.

Referenced by [8], [9], [14].

[2] bccb=1

Axiom: bccb=1.

Referenced by [4].

[3] cb=d

Axiom: cb=d.

Defines rule #2.

Referenced by [4], [5], [10], [15].

[4] bcd=1

Overlap of [2] bccb=1 with [3] cb=d:

bc cb cb

Critical pair: bcd=1.

Defines rule #5.

Referenced by [5], [6], [8], [10], [12].

[5] dcd=c

Overlap of [3] cb=d with [4] bcd=1:

c b bcd

Critical pair: c=dcd.

Flip LHS and RHS.

Defines rule #4.

Referenced by [6], [7], [13].

[6] bcc=cd

Overlap of [4] bcd=1 with [5] dcd=c:

bc d dcd

Critical pair: bcc=cd.

Defines rule #3.

Referenced by [9], [10], [11].

[7] dcc=ccd

Overlap of [5] dcd=c with [5] dcd=c:

dc d dcd

Critical pair: dcc=ccd.

Defines rule #1.

[8] aacd=a

Overlap of [1] ab=aa with [4] bcd=1:

a b bcd

Critical pair: a=aacd.

Flip LHS and RHS.

Defines rule #11.

Referenced by [14].

[9] aacc=acd

Overlap of [1] ab=aa with [6] bcc=cd:

a b bcc

Critical pair: acd=aacc.

Flip LHS and RHS.

Defines rule #6.

[10] cdb=1

Overlap of [6] bcc=cd with [3] cb=d:

bc c cb

Critical pair: bcd=cdb.

Reduce LHS:

[4](bcd)
⇒ 1

Flip LHS and RHS.

Defines rule #7.

Referenced by [11], [13].

[11] cddb=bc

Overlap of [6] bcc=cd with [10] cdb=1:

bc c cdb

Critical pair: bc=cddb.

Flip LHS and RHS.

Referenced by [12], [13], [14].

[12] bbc=db

Overlap of [4] bcd=1 with [11] cddb=bc:

b cd cddb

Critical pair: bbc=db.

Defines rule #10.

Referenced by [17].

[13] dbc=1

Overlap of [5] dcd=c with [11] cddb=bc:

d cd cddb

Critical pair: dbc=cdb.

Reduce RHS:

[10](cdb)
⇒ 1

Defines rule #8.

Referenced by [15].

[14] adb=aaac

Overlap of [8] aacd=a with [11] cddb=bc:

aa cd cddb

Critical pair: aabc=adb.

Reduce LHS:

[1]a(ab)c
⇒ aaac

Flip LHS and RHS.

Defines rule #14.

[15] dbd=b

Overlap of [13] dbc=1 with [3] cb=d:

db c cb

Critical pair: dbd=b.

Defines rule #12.

Referenced by [16].

[16] dbb=bbd

Overlap of [15] dbd=b with [15] dbd=b:

db d dbd

Critical pair: dbb=bbd.

Defines rule #15.

Referenced by [17].

[17] ddb=bbdc

Overlap of [16] dbb=bbd with [12] bbc=db:

d bb bbc

Critical pair: ddb=bbdc.

Defines rule #13.