Morphocompletion for #3040 ⟨a, b, c | aba=b, bcb=c⟩

Solved by morph:3/3. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: roundsLimit

#Rule
1. bba ⇒ abb
2. aba ⇒ b
3. bcb ⇒ c
4. bcabb ⇒ cba
5. bcaabb ⇒ cbaa
6. bcaaabb ⇒ cbaaa
7. bcaaaabb ⇒ cbaaaa
8. bcaaaaabb ⇒ cbaaaaa
9. bcaaaaaabb ⇒ cbaaaaaa
10. bcc ⇒ ccb
11. bcac ⇒ cbacbb
12. bcabc ⇒ cbacb
13. bcaac ⇒ cbaacbb
14. bcaabc ⇒ cbaacb
15. bcaaac ⇒ cbaaacbb
16. bcaaabc ⇒ cbaaacb
17. bcaaaac ⇒ cbaaaacbb
18. bcaaaabc ⇒ cbaaaacb
19. bcaaaaac ⇒ cbaaaaacbb
20. bcaaaaabc ⇒ cbaaaaacb
...

Collecting factors up to length 4 / frequency 7:

[2/0]bc46lf:23,lp:18,ls:5,a:1
[2/1]aa35lf:35,rf:35,rs:5,a:6
[2/2]ca16lf:16,a:4
[2/3]bb14lf:7,lp:1,ls:6,rf:6,rs:6,lprs:10,a:2
[2/4]ab13lf:12,lp:1,rf:1,rp:1
[2/5]ac10lf:5,ls:5,rf:10,a:5
[2/6]ba4lf:2,ls:2,rf:16,rs:1
[3/0]bca32lf:16,lp:16,a:4
[3/1]aaa22lf:22,rf:22,rs:4,a:8
[3/2]caa13lf:13,a:6
[3/3]abb12lf:6,ls:6,rf:1,rp:1,rs:1,re:1,a:2
[3/4]abc10lf:5,ls:5,a:5
[3/5]aab9lf:9,a:6
[3/6]aac8lf:4,ls:4,rf:8,a:7

Considering [length 3 / frequency 3] abb=d.

Step 2

Rewriting system is complete. See ⟨a, b, c | aba=b, bcb=c⟩.