Morphocompletion for #2904 ⟨a, b, c | aab=a, cbc=a⟩

Solved by morph:2/1. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: roundsLimit

#Rule
1. cbc ⇒ a
2. abc ⇒ cba
3. aab ⇒ a
4. acab ⇒ ac
5. acba ⇒ ac
6. accab ⇒ acc
7. accba ⇒ acc
8. acccab ⇒ accc
9. acccba ⇒ accc
10. accccab ⇒ acccc
11. accccba ⇒ acccc
12. acccccab ⇒ accccc
13. acccccba ⇒ accccc
14. accccccab ⇒ acccccc
15. accccccba ⇒ acccccc
16. acccccccab ⇒ accccccc
17. acccccccba ⇒ accccccc
18. accccccccab ⇒ acccccccc
19. accccccccba ⇒ acccccccc
20. acccccccccab ⇒ accccccccc
...

Collecting factors up to length 4 / frequency 7:

[2/0]cc64lf:64,rf:64,rs:15,a:5
[2/1]ac34lf:17,lp:17,rf:17,rp:17,rs:2,re:2,lprp:17,lprs:2,a:3
[2/2]ab22lf:11,lp:1,ls:10
[2/3]ba16lf:8,ls:8,rf:1,rs:1,a:2
[2/4]cb10lf:9,lp:1,rf:1,rp:1,a:1
[2/5]ca9lf:9,a:4
[2/6]bc4lf:2,ls:2,a:1
[3/0]ccc49lf:49,rf:49,rs:13,a:7
[3/1]acc30lf:15,lp:15,rf:15,rp:15,rs:2,re:2,lprp:15,lprs:2,a:5
[3/2]cab18lf:9,ls:9,a:4
[3/3]cba16lf:8,ls:8,rf:1,rp:1,rs:1,re:1,a:2
[3/4]cca8lf:8,a:6
[3/5]ccb7lf:7,a:5
[3/6]aca2lf:1,lp:1,a:4

Considering [length 2 / frequency 1] ac=d.

Step 2

Rewriting system is complete. See ⟨a, b, c | aab=a, cbc=a⟩.