Certificate for #2904 ⟨a, b, c | aab=a, cbc=a⟩

Completion settings:

[1] aab=a

Axiom: aab=a.

Referenced by [6].

[2] cbc=a

Axiom: cbc=a.

Referenced by [4], [5], [7], [9], [12], [16].

[3] ac=d

Axiom: ac=d.

Referenced by [5], [7].

[4] abc=cba

Overlap of [2] cbc=a with [2] cbc=a:

cb c cbc

Critical pair: cba=abc.

Flip LHS and RHS.

Referenced by [11].

[5] aa=dbc

Overlap of [3] ac=d with [2] cbc=a:

a c cbc

Critical pair: aa=dbc.

Referenced by [6], [8].

[6] a=dbcb

Simplify [1] aab=a.

Reduce LHS:

[5](aa)b
⇒ dbcb

Flip LHS and RHS.

Defines rule #4.

Referenced by [7], [8], [9], [11], [12], [16].

[7] dbdbcb=d

Overlap of [3] ac=d with [6] a=dbcb:

ac a

Critical pair: dbcbc=d.

Reduce LHS:

[2]db(cbc)
[6]⇒ db(a)
⇒ dbdbcb

Referenced by [9], [12], [13], [14], [15].

[8] dbcbdbcb=dbc

Simplify [5] aa=dbc.

Reduce LHS:

[6](a)a
[6]⇒ dbcb(a)
⇒ dbcbdbcb

Referenced by [9], [10], [14].

[9] dbcc=dbcbd

Overlap of [8] dbcbdbcb=dbc with [2] cbc=a:

dbcbdb cb cbc

Critical pair: dbcbdba=dbcc.

Reduce LHS:

[6]dbcbdb(a)
[7]⇒ dbcb(dbdbcb)
⇒ dbcbd

Flip LHS and RHS.

Defines rule #6.

[10] dbcbdbc=dbcdbcb

Overlap of [8] dbcbdbcb=dbc with [8] dbcbdbcb=dbc:

dbcb dbcb dbcbdbcb

Critical pair: dbcbdbc=dbcdbcb.

Defines rule #9.

Referenced by [13].

[11] dbcbbc=cbdbcb

Simplify [4] abc=cba.

Reduce LHS:

[6](a)bc
⇒ dbcbbc

Reduce RHS:

[6]cb(a)
⇒ cbdbcb

Defines rule #7.

Referenced by [13].

[12] dc=dbd

Overlap of [7] dbdbcb=d with [2] cbc=a:

dbdb cb cbc

Critical pair: dbdba=dc.

Reduce LHS:

[6]dbdb(a)
[7]⇒ db(dbdbcb)
⇒ dbd

Flip LHS and RHS.

Defines rule #1.

[13] dbcdbcbb=dbc

Overlap of [7] dbdbcb=d with [11] dbcbbc=cbdbcb:

db dbcb dbcbbc

Critical pair: dbcbdbcb=dbc.

Reduce LHS:

[10](dbcbdbc)b
⇒ dbcdbcbb

Defines rule #8.

[14] dbdbc=ddbcb

Overlap of [7] dbdbcb=d with [8] dbcbdbcb=dbc:

db dbcb dbcbdbcb

Critical pair: dbdbc=ddbcb.

Defines rule #3.

Referenced by [15].

[15] ddbcbb=d

Overlap of [7] dbdbcb=d with [14] dbdbc=ddbcb:

dbdbcb dbdbc

Critical pair: ddbcbb=d.

Defines rule #2.

[16] cbc=dbcb

Simplify [2] cbc=a.

Reduce RHS:

[6](a)
⇒ dbcb

Defines rule #5.