Morphocompletion for #2777 ⟨a, b, c | abc=b, acca=1⟩

Solved by morph:2/0. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: roundsLimit

#Rule
1. ccb ⇒ bcc
2. abc ⇒ b
3. abbcc ⇒ bcb
4. abbbcc ⇒ bcbb
5. bcab ⇒ abbc
6. cca ⇒ acc
7. bcbab ⇒ abbbc
8. aacc ⇒ 1
9. aabbc ⇒ bab
10. aacbc ⇒ cab
11. aabbbc ⇒ bbab
12. aacbbc ⇒ cbab
13. aacbcc ⇒ cb
14. abacc ⇒ bca
15. baa ⇒ aab
16. caa ⇒ aac
17. bcaa ⇒ ab
18. aacacc ⇒ ca
...

Collecting factors up to length 4 / frequency 7:

[2/0]aa20lf:10,lp:7,ls:3,rf:2,rp:2,lsrp:20,a:11
[2/1]bc19lf:11,lp:3,ls:5,rf:6,rp:4,rs:2,lprs:2
[2/2]cc16lf:8,lp:2,ls:6,rf:2,rs:2,lprs:20,a:3
[2/3]ab14lf:8,lp:4,ls:2,rf:8,rp:3,rs:6,re:1,lsrp:2
[2/4]ca7lf:5,lp:1,ls:1,rf:3,rp:2,rs:2,re:1,a:3
[2/5]ac7lf:7,rf:2,rp:1,rs:1,a:3
[2/6]bb7lf:7,rf:5,rp:1,rs:1,a:5
[3/0]aac10lf:5,lp:5,rf:1,rp:1,rs:1,re:1,a:18
[3/1]bbc8lf:5,ls:3,rf:2,rs:2,a:5
[3/2]acc6lf:3,ls:3,rf:1,rp:1,rs:1,re:1,a:3
[3/3]abb6lf:4,lp:2,rf:2,rp:2,a:5
[3/4]bcc6lf:3,ls:3,rf:1,rp:1,rs:1,re:1,a:4
[3/5]aab4lf:2,lp:2,rf:1,rp:1,rs:1,re:1,a:16
[3/6]bca4lf:2,lp:2,rf:1,rp:1,rs:1,re:1,a:6

Considering [length 2 / frequency 0] aa=d.

Step 2

Rewriting system is complete. See ⟨a, b, c | abc=b, acca=1⟩.