Certificate for #2625 ⟨a, b, c | aba=b, cacc=1⟩

Completion settings:

[1] aba=b

Axiom: aba=b.

Referenced by [5], [10].

[2] cacc=1

Axiom: cacc=1.

Referenced by [3], [4], [8].

[3] acc=cac

Overlap of [2] cacc=1 with [2] cacc=1:

cac c cacc

Critical pair: cac=acc.

Flip LHS and RHS.

Referenced by [4].

[4] ac=ca

Overlap of [3] acc=cac with [2] cacc=1:

ac c cacc

Critical pair: ac=cacacc.

Reduce RHS:

[2]ca(cacc)
⇒ ca

Defines rule #1.

Referenced by [5], [6], [7], [8].

[5] abca=bc

Overlap of [1] aba=b with [4] ac=ca:

ab a ac

Critical pair: abca=bc.

Referenced by [6].

[6] abcca=bcc

Overlap of [5] abca=bc with [4] ac=ca:

abc a ac

Critical pair: abcca=bcc.

Referenced by [7].

[7] abccca=bccc

Overlap of [6] abcca=bcc with [4] ac=ca:

abcc a ac

Critical pair: abccca=bccc.

Referenced by [9].

[8] ccca=1

Overlap of [2] cacc=1 with [4] ac=ca:

c acc ac

Critical pair: ccac=1.

Reduce LHS:

[4]cc(ac)
⇒ ccca

Defines rule #2.

Referenced by [9], [10].

[9] ab=bccc

Overlap of [7] abccca=bccc with [8] ccca=1:

ab ccca ccca

Critical pair: ab=bccc.

Defines rule #3.

[10] cccb=ba

Overlap of [8] ccca=1 with [1] aba=b:

ccc a aba

Critical pair: cccb=ba.

Defines rule #4.